Select the additive identity property from the following.

a

\times

1 =

a

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\frac{a}{1}

a

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a - a = 0

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a + 0 = a

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Solution

The correct option is D $a + 0 = a$
The additive identity states that if you add an integer to zero or add zero to an integer, its value does not change.
For example,
$2 + 0 = 2$
Hence $0$ is the additive identity for all integers.

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(a - \frac{1}{a}) (a - \frac{1}{a})

∣ ∣ ∣ ∣ \begin{matrix} a - b & b - c & c - a b - c & c - a & a - b c - a & a - b & b - c \end{matrix} ∣ ∣ ∣ ∣

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Which of the following is not the additive inverse of a?

(a) $- (- a)$
(b) $a \times (- 1)$
(c) $- a$
(d) $a \div (- 1)$

Given a_{1} = \frac{1}{2} (a_{0} + \frac{A}{a_{0}}), a_{2} = \frac{1}{2} (a_{1} + \frac{A}{a_{1}}) and a_{n + 1} = \frac{1}{2} (a_{n} + \frac{A}{a_{n}}) for n \geq 2, where a > 0, A > 0 . Prove that \frac{a_{n} - \sqrt{A}}{a_{n} + \sqrt{A}} = (\frac{a_{1} - \sqrt{A}}{a_{1} + \sqrt{A}}) 2^{n - 1} .

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