Select the correct algebraic identities.

$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

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$(a + b)^{2} = a^{2} - b^{2} - 2 a b$

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$(a - b)^{2} = a^{2} + b^{2} - 2 a b$

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$a^{2} - b^{2} = (a + b) (a - b)$

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Solution

The correct options are
A
$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

C
$(a - b)^{2} = a^{2} + b^{2} - 2 a b$

D
$a^{2} - b^{2} = (a + b) (a - b)$

Right algebraic identities are

$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

$(a - b)^{2} = a^{2} + b^{2} - 2 a b$

$a^{2} - b^{2} = (a + b) (a - b)$

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Similar questions

Q. Show that :

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}} = \frac{b^{2}}{d^{2}}

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

What is the value of $(a + b) (a - b) ?$

Q. If θ =

\frac{a}{b}

, then

\frac{(a sinθ - b cosθ)}{(a \sin θ + b cosθ)}

= ?
(a)

\frac{(a^{2} + b^{2})}{(a^{2} - b^{2})}

(b)

\frac{(a^{2} - b^{2})}{(a^{2} + b^{2})}

(c)

\frac{a^{2}}{(a^{2} + b^{2})}

(d)

\frac{b^{2}}{(a^{2} + b^{2})}

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Select the correct algebraic identities.

The correct options are A (a+b)2=a2+b2+2ab C (a−b)2=a2+b2−2ab D a2−b2=(a+b)(a−b) Right algebraic identities are (a+b)2=a2+b2+2ab (a−b)2=a2+b2−2ab a2−b2=(a+b)(a−b)

The correct options are
A
$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

C
$(a - b)^{2} = a^{2} + b^{2} - 2 a b$

D
$a^{2} - b^{2} = (a + b) (a - b)$

Right algebraic identities are

$(a + b)^{2} = a^{2} + b^{2} + 2 a b$

$(a - b)^{2} = a^{2} + b^{2} - 2 a b$

$a^{2} - b^{2} = (a + b) (a - b)$