Select the correct alternative.

In the reaction of $Z n + F e S O_{4} \to Z n S O_{4} + F e$

Zn gets oxidized

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Fe gets oxidized

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Zn is oxidized in agent

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Zn and Fe both get oxidized

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Solution

The correct option is C Zn gets oxidized
Since in this reaction with zinc metal i.e. the reactant of the oxidation reaction is providing the electron required to reduce the iron, the zinc is the reducing agent and the zinc itself is oxidized.

$Z n \to Z n^{2 +} + 2 e^{-}$ and $F e^{2 +} + 2 e^{-} \to F e$

$F e S O_{4} \to F e^{2 +} + S O_{4}^{2 -}$

$Z n^{2 +} + S O_{4}^{2 -} \to Z n S O_{4}$

So, the correct option is $A$

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Z n + F e S O_{4} \to Z n S O_{4} + F e

C u S O_{4} + F e \to F e S O_{4} + C u

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F e S O_{4} + Z n \to Z n S O_{4} + F e

Z n (s) + C u S O_{4} (a q) \to Z n S O_{4} (a q) + C u (s)

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