Correct Answer: (D) lead (Ⅱ) bromide.
The reaction takes place during the electrolysis of molten lead (Ⅱ) bromide are,
At cathode: Pb2++2e−→Pb
At anode: Br−−e−→Br
Br+Br→Br2
The overall reaction is
PbBr2 (l)→Pb (s)+Br2 (g)
Here bromine gas evolves anode which has a reddish-brown colour.