Question

Select the correct combination of mathematical signs to replace $\ast$ signs to balance the given equation.
$4^{\ast }{7}^{\ast }{10}^{\ast }{5}^{\ast }{3}^{\ast }{7}^{\ast }47$

• A. $\times -÷+\times =$
• B. $-+÷\times -=$
• C. $+\times -÷\times =$
• D. $÷\times +-+=$

Answer 1

The correct option is A $\times -÷+\times =$

$4\times 7-10÷5+3\times 7=47$
$4\times 7-2+3\times 7=47$
$28-2+21=47$
$28+21-2=47$
$49-2=47$
$47=47$.