Select the correct I.E. order for the following species.

C l > B r

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B r^{-} > C l^{-}

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C l > C l^{-}

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B r > B r^{-}

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Solution

The correct options are
A $C l > B r$
C $C l > C l^{-}$
D $B r > B r^{-}$
(A) $C l > B r$ is correct because Size of $C l$ is smaller than $B r$ so it requires more energy for the removal of electron hence more will be the ionization potential.
(B) $B r^{-} > C l^{-}$ is the wrong statement because as the size of the $C l^{-}$ is less $C l^{-}$ should have more IP value
(C). $C l > C l^{-}$ correct because I.E. of a neutral atom is more than anion
(D). $B r > B r^{-}$ correct because I.E. of a neutral atom is more than anion
Hence options $A, C$ and $D$ are correct.

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