Question

Select the correct I.U.P.A.C name for $\left[Pt\right(C_5{H}_{5}N{)}_4\left]\right[PtC{l}_4]$ :

• A. Tetrapyridineplatinate $\left(II\right)$ tetrachloridoplatinate $\left(II\right)$
• B. Tetrapyridineplatinum $\left(II\right)$ tetrachloridoplatinum $\left(II\right)$
• C. Tetrapyridineplatinate $\left(II\right)$ tetrachloridoplatinum $\left(II\right)$
• D. Tetrapyridineplatinum $\left(II\right)$ tetrachloridoplatinate $\left(II\right)$

Answer 1

Answer: (D)

Tetrapyridineplatinum $\left(II\right)$ tetrachloridoplatinate $\left(II\right)$

In the complex, pyridine is neutral ligand and chloride has -1 charge. So overall, the charge of both the complex is +2 on first platinum and -2 on second platinum. So it is named as platinate and oxidation states are written in roman letters within the brackets.

Option (D) is correct. The correct I.U.P.A.C name for $\left[Pt\right(C_5{H}_{5}N{)}_4\left]\right[PtC{l}_4]$ is Tetrapyridineplatinum $\left(II\right)$ tetrachloridoplatinate $\left(II\right)$