Question

Select the correct IUPAC name for $Cr\left(C_6{H}_6\right){\left(CO\right)}_3$.

• A. (${\eta }^6$-benzene) tricarbonylchromate(0)
• B. Tricarbonyl (${\eta }^6$-benzene)chromate(0)
• C. Tricarbonyl (${\eta }^6$-benzene)chromium(0)
• D. (${\eta }^6$-benzene) tricarbonylchromium(0)

Answer 1

Answer: (D)

(${\eta }^6$-benzene) tricarbonylchromium(0)

The correct I.U.P.A.C name for $Cr\left(C_6{H}_6\right){\left(CO\right)}_3$ (${\eta }^6$-benzene) tricarbonylchromium(0). Benzene donates 6 eectrons. Hence, its hepticity is 6 .
three carbonyl groups are present.
The oxidation state of $Cr$ is written in parenthesis.