Question

Select the correct option, among $Sc\left(III\right),Ti\left(IV\right),Pd\left(II\right)$ and $Cu\left(II\right)$ ions.

• A. All are paramagnetic
• B. All are diamagnetic
• C. $Sc\left(III\right),Ti\left(IV\right)$ are paramagnetic and $Pd\left(III\right),Cu\left(II\right)$ are diamagnetic
• D. $Sc\left(III\right),Ti\left(IV\right)$ are diamagnetic and $Pd\left(II\right),Cu\left(II\right)$ are paramagnetic

Answer 1

The correct option is D $Sc\left(III\right),Ti\left(IV\right)$ are diamagnetic and $Pd\left(II\right),Cu\left(II\right)$ are paramagnetic

${SC}^{3+}\left({\left[Ar\right]3d}^0\right)$ ] $\to$ since no unpaired electrons so diamagnetic

${Ti}^{4+}\left(\right[Ar\left]{3d}^0\right)$ ] $\to$ since no unpaired electrons so diamagnetic

${Pd}^{2+}\left(\right[Kr\left]{4d}^8\right)$ ] $\to$ since there is unpaired electrons so paramagnetic

${Cu}^{2+}\left(\right[Ar\left]{3d}^9\right)$ ] $\to$ since there is unpaired electrons so paramagnetic.

So, the correct option is D.