Select the correct option given below:
From the graph , $O A^{2} =$

0

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a^{2} + b^{2}

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\sqrt{a^{2} + b^{2}}

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\sqrt{a + b}

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Solution

The correct option is C $\sqrt{a^{2} + b^{2}}$
As shown in figure, the co-ordinates of point A is (a,b)
Draw $¯ A M ⊥ - - \to O X$
$∴ O M = a$ and $A M = b$
$△ A M O$ is a right angle triangle.
$∴$ by Pythagoras' theorem, $O A^{2} = O M^{2} + A M^{2}$
$∴ O A^{2} = a^{2} + b^{2}$
$∴ O A = \sqrt{a^{2} + b^{2}}$

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Q. Choose the correct option for the given equation.

(a + b)^{2} = a^{2} + 2 a b + b^{2}

Which of the following is correct?
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b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

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\frac{a}{b}

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(b)

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Q. The squares of two natural numbers a, b are 529 and 841. It is given that a > b. Choose the correct options.

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Select the correct option given below:From the graph ,OA2=

The correct option is C √a2+b2As shown in figure, the co-ordinates of point A is (a,b) Draw ¯AM⊥−−→OX ∴OM=a and AM=b△AMO is a right angle triangle.∴ by Pythagoras' theorem, OA2=OM2+AM2∴OA2=a2+b2∴OA=√a2+b2

Select the correct option given below:
From the graph , $O A^{2} =$