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Question

Select the correct option given below:When 1.5kg of ice at 0oC mixed with 2kg of water at 70oC in a container, the resulting temperature is 5oC the heat of fusion of ice is (swater=4186JKg−1K−1)

A
1.42×105Jkg1
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B
2.42×105Jkg1
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C
3.42×105Jkg1
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D
4.42×105Jkg1
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Solution

The correct option is C 3.42×105Jkg−1Heat lost by water =mwsw(T2−Tf)=2×4186×(70−5)=544180JHeat required to melt ice=miLf=1.5×LfHeat required to rise temperature of ice⇒misw(Tf−T0)=1.5×(4186)×(5−0o)=31395JBy the principle of calorimetryheat lost = heat gained544180=1.5Lf+31395∴Lf=5127851.5=341856.67=3.42×105Jkg−1

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