Select the correct sequence of formation of given intermediates of Krebs' cycle.
A
Succinate→Malate→Fumarate→OAA
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B
Fumarate→Succinate→Malate→OAA
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C
Succinate→Fumarate→Malate→OAA
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D
Malate→Fumarate→Succinate→OAA
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Solution
The correct option is DSuccinate→Fumarate→Malate→OAA In Kreb's cycle:
1. Dehydrogenation: This process converts succinate into 4 carbon fumarate with the aid of enzyme, succinate dehydrogenase, and liberates a pair of hydrogen atoms.
2. Hydration. This process changes fumarate into 4- carbon maltate in the presence of water and an enzyme furmarase.
3. Dehydrogenation: This process restores oxaloacetate by removing a pair of hydrogen atoms from maltate with the help of an enzyme maltate dehydrogenase.
So, the correct answer is 'Succinate → Fumarate →Malate → OAA'.