Select the correct options in view of the following reaction:

$Z n C l_{2}$ acts as Lewis acid

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The reaction proceeds via $S_{N} 2$

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The products are racemic

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The products are optically active

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Solution

The correct options are
A
$Z n C l_{2}$ acts as Lewis acid

D
The products are optically active

A tertiary alcohol is treated with $Z n C l_{2}$ – which acts as a Lewis acid in this reaction.
In an $S_{N} 1$ , the OH group departs leaving behind a stable tertiary carbocation,
which is attacked by chloride. Since the carbocation is attacked on either side, the products are:

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