Select the correct order in relation with the bond length

O_{2} > H_{2} O_{2} > O_{3}

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H_{2} O_{2} >> O_{3} > O_{2}

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O_{3} > H_{2} O_{2} > O_{2}

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H_{2} O_{2} > O_{2} > O_{3}

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Solution

The correct option is C $O_{2} > H_{2} O_{2} > O_{3}$

The bond length decreases with the increase of bond orderBond order is 1 if it is a single bond,bond order is 2 if it is a double bond and bond order is three if it is a triple bond. $H_{2} O_{2}$ has all single bonds with the bond length of 1.41 and $O_{2}$ has a double bond with Bond length of 1.33 and $O_{3}$ has a partial double bond due to resonance of lone pairs of electrons

If we arrange the above molecules according to their bond lengths it would be $H_{2} O_{2} > O_{3} > O_{2}$ .
Hence option B is correct.

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