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Question

Select the correct order of 2nd ionization energy of C, N, O, and F.

A
C > N > O > F
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B
N > C > O > F
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C
C < N < O < F
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D
O > F > N > C
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Solution

The correct option is C O > F > N > C
Consider the configurations of the given elements after the loss of an electron.
C+ : 1s22s22p1
N+ : 1s22s22p2
O+ : 1s22s22p3
F+ : 1s22s22p4
We notice that O has a half-filled orbital and hence has the highest I.E. among these. Also, carbon can lose an electron easily. Fluorine will reach a half-filled configuration upon the loss of an electron. Hence, the order is O>F>N>C.

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