Select the correct order of acidic strength.

B F_{3} > M e_{3} B

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H C \equiv C - H (s p c a r b o n) < H_{2} C = C H - H (s p^{2} c a r b o n) < H_{3} C - C H_{2} - H (s p^{3} c a r b o n)

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B F_{3} < M e_{3} B

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H C \equiv C - H (s p c a r b o n) > H_{2} C = C H - H (s p^{3} c a r b o n) > H_{3} C - C H_{2} - H (s p^{3} c a r b o n)

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Solution

The correct options are
C $B F_{3} > M e_{3} B$
D $H C \equiv C - H (s p c a r b o n) > H_{2} C = C H - H (s p^{3} c a r b o n) > H_{3} C - C H_{2} - H (s p^{3} c a r b o n)$
Select the correct order of acidic strength is $B F_{3} > M e_{3} B$
Thus, the option A is correct and option C is incorrect.
Select the correct order of acidic strength is $H C \equiv C - H (s p c a r b o n) > H_{2} C = C H - H (s p^{3} c a r b o n) > H_{3} C - C H_{2} - H (s p^{3} c a r b o n)$
Thus, the option D is correct and option B is incorrect.

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H C \equiv C H

H_{2} C = C H_{2}

H_{3} C - C H_{3}

C H_{3} C H_{3} > C H_{2} = C H_{2} > H C = C h

C - C

H C \equiv C - C H = C H_{2}

H C \equiv C - C H_{2} - C H_{2} = C H C H_{2} - | C = C H - H | C = O

C H_{3} - C H_{3}, C H_{2} = C H - C H_{3}, H C \equiv C - C H_{3}

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