You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trend in Ionisation Enthalpy

Select the co...

Question

Select the correct order of first ionization potential :

N_{2} > O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2} > O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

O > O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

O_{2} \approx N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $O > O_{2}$
C $N_{2} > O_{2}$
D $N_{2} > O$
A) The first ionization potential of nitrogen molecule is higher than the first ionization potential of oxygen molecule as nitrogen molecule contains a triple bond which is stronger than the double bond between $O$ atoms. Hence, the option A is correct and the option D is incorrect.
B) The first ionization potential of nitrogen molecule is higher than that of oxygen atom as in nitrogen molecule; the electron is attracted by two nuclei. Hence, the option B is correct.
C) The first ionization potential of oxygen atom is greater than that of oxygen molecule as in oxygen molecule; the electron is removed from antibonding pi orbital which requires less energy. Thus, the option C is correct.

Suggest Corrections

Similar questions

$N_{2}$ and $O_{2}$ are converted into monocations, $N_{2}^{+}$ and $O_{2}^{+}$ respectively. Which of the following is wrong ?

N_{2} > N

I^{s t}

O_{2} > O

I^{s t}

H_{2} > H

I^{s t}

N_{2}^{+} > N_{2}^{-}

H_{2} > H

I^{s t}

N a_{2} C O_{3} > L i_{2} C O_{3}

S T P

H_{2}, N_{2}, O_{2}

H B r

N_{2}

O_{2}

O_{2}^{+}

{O_{2}}^{-}

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$ ?

(i). $N_{2} \to N_{2}^{+} + e^{-}$

(ii) $O_{2} \to O_{2}^{+} + e^{-}$

Join BYJU'S Learning Program