Select the correct order of magnetic moment (in B.M.) from the following options:

$[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$

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$[F e (C N)_{6}]^{4 -} > [M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -}$

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$[F e (C N)_{6}]^{2 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -}$

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$[M n C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -} > [C o C l_{4}]^{2 -}$

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Solution

The correct option is A
$[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$

$[M n C l_{4}]^{2 -} : p > Δ_{t}; d^{5} - s y s t e m μ_{e f f} = 5.9 B . M [C o C l_{4}]^{2 -} : P > Δ_{t}; d^{7} - s y s t e m μ_{e f f} = 3.89 B . M [F e (C N)_{6}]^{4 -} : P < Δ_{0}; d^{6} - s y s t e m μ_{e f f} = 0 B . M$

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