Select the correct order of magnetic moment (in B.M.) from the following options :

[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}

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[F e (C N)_{6}]^{4 -} > [M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -}

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[F e (C N)_{6}]^{4 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -}

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[M n C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -} > [C o C l_{4}]^{2 -}

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Solution

The correct option is A $[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$
The correct order of magnetic moment (in B.M.) is $[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [F e (C N)_{6}]^{4 -}$
$[M n C l_{4}]^{2 -}$ has $3 d^{5}$ orbitals and 5 unpaired electron.

$[C o C l_{4}]^{2 -}$ has $3 d^{7}$ orbitals and 3 unpaired electron.
$[F e (C N)_{6}]^{4 -}$ has $3 d^{6}$ orbitals and 0 unpaired electrons.

More the number of unpaired electrons more is the magnetic moment.

Option (A) is correct.

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Similar questions

M n = 25; F e = 26; C o = 27

18

[C u (N H_{3})_{4}]^{2 +}, [C u (e n)_{3}]^{2 +}, [C u (C N)_{4}]^{3 -}

[F e (C N)_{6}]^{4 -}, [F e (C N)_{6}]^{3 -}, F e (C O)_{6}

[N i (N H_{3})_{6}]^{2 +}, [N i (C N)_{4}]^{2 -}, [N i (C O)_{4}]

[C r (N H_{3})_{6}]^{3 +}, [C r (C O)_{6}]

[C o (N H_{3})_{6}]^{3 +}, [C o C l_{4}]^{2 -}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[N i (C N)_{4}]^{2 -}

[N i (H_{2} O)_{4}]^{2 +}

[F e (C N)_{6}]^{4 -}

[F e (H_{2} O)_{6}]^{2 +}

Magnetic moment of $[M n C l_{4}]^{2 -}$ is 5.92 BM. Explain giving reason present.

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