Question

Select the correct order with respect to boiling point of the given compounds.

• A. $H_{2}O>H_{2}S>H_{2}Se>H_{2}Te$
• B. $H_{2}O>H_{2}Te>H_{2}Se>H_{2}S$
• C. $H_{2}Te>H_{2}Se>H_{2}S>H_{2}O$
• D. $H_{2}S>H_{2}O>H_{2}Te>H_{2}Se$

Answer 1

Answer: (B)

$H_{2}O>H_{2}Te>H_{2}Se>H_{2}S$

We know that as the molecular mass of the compound increases, boiling point also increases.

However, due to very strong hydrogen bonding interactions in water, it has the highest boiling point of all.

Hence, the correct order is as follows:

$H_{2}O>H_{2}Te>H_{2}Se>H_{2}S$

Option B is correct.