Select the correct order with respect to lattice energy of alkali metals fluorides:
A
RbF<KF<NaF<LiF<CsF
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B
KF<NaF<LiF<CsF<RbF
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C
NaF<LiF<CsF<RbF<KF
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D
CsF<RbF<KF<NaF<LiF
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Solution
The correct option is DCsF<RbF<KF<NaF<LiF In the given alkali metal halides, the anion is the same (F− ion). Lattice energy depends on the size of the cation. It is inversely proportional to the size of the cation.
Thus, as the size of the cation increases, the lattice energy decreases. Therefore, the smallest size is of Li+ and hence, LiF will have the highest lattice energy.