Select the correct orders of bond angles.

H -^P - H (P H_{3}) < F -^P - F (P F_{3})

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F -^N - F (N F_{3}) < H -^N - F (N H_{3})

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F -^O - F (O F_{3}) < H -^O - H (H_{2} O) < C l -^O - C l (O C l_{2})

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H -^P - H (P H_{3}) > F -^P - F (P F_{3})

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Solution

The correct options are
A $H -^P - H (P H_{3}) < F -^P - F (P F_{3})$
B $F -^N - F (N F_{3}) < H -^N - F (N H_{3})$
C $F -^O - F (O F_{3}) < H -^O - H (H_{2} O) < C l -^O - C l (O C l_{2})$
(A) The correct order of bond angles is:
$H -^P - H (P H_{3}) < F -^P - F (P F_{3})$
F being more electronegative attracts bond pair of electrons towards itself. Hence, these electrons experience less repulsion with a lone pair of electrons.
Hence, option A is correct.
(B) The correct order of bond angles is:
$F -^N - F (N F_{3}) < H -^N - F (N H_{3})$
F being more electronegative attracts bond pair of electrons towards itself. Hence, these electrons experience less repulsion with electrons of another bond.
Hence, the option B is correct.
(C) The correct order of bond angles is:
$F -^O - F (O F_{3}) < H -^O - H (H_{2} O) < C l -^O - C l (O C l_{2})$
Hence, the option C is correct. (This is a bit data-based)

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