The correct option is D IE of Al in AlF3>AlCl3
Electronegativity is the reason for that. Electronegativity of Aluminum has a value of around 1.5; fluoride around 4, and chloride around 3.
In aluminium fluoride, the difference between a F and Al, in terms of electronegativity, is 2.5 In aluminium chloride, it is 1. So a bond is covalent is this difference in EN is less than 1.2, is
polar from a difference of 1.2 to 1.8, and ionic for a difference of 1.8 and greater.