Select the correct relation.

$I . E ._{1} (C u) < I . E ._{1} (Z n) b u t I . E ._{2} (C u) > I . E ._{2} (Z n)$

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$I . E ._{1} (C u) < I . E ._{1} (Z n) a n d I . E ._{2} (C u) < I . E ._{2} (Z n)$

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$I . E ._{1} (C u) > I . E ._{1} (Z n) a n d I . E ._{2} (C u) > I . E ._{2} (Z n)$

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$I . E ._{1} (C u) > I . E ._{1} (Z n) a n d I . E ._{2} (C u) > I . E ._{2} (Z n)$

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Solution

The correct option is A
$I . E ._{1} (C u) < I . E ._{1} (Z n) b u t I . E ._{2} (C u) > I . E ._{2} (Z n)$

$C u : [A r] 3 d^{10}, 4 s^{1}; C u^{+} : [A r] 3 d^{10}; C u^{2} : [A r] 3 d^{9};$
$Z n : [A r] 3 d^{10}; Z n^{+} : [A r] 3 d^{10}, 4 s^{2}$
Removal of successive electron in Cu takes place from 4s and 3d-orbitals and thus due to change in major energy shell $I P^{2}$ values of Cu shows a jump. In Zn, the removal of successive electrons takes place from 4s-orbital and thus no jump in $I P^{2}$ values is noticed.

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