Select the correct statement about given square planar complex :

It has no geometrical isomer

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It is optically active because it does not have plane of symmetry

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It is optically inactive because square planar complex have plane of symmetry

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It is optically active because is has symmetric carbon

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Solution

The correct option is B It is optically active because it does not have plane of symmetry
For the given compound two geometrical isomers are possible on is cis and the other is trans.
The molecule does not contain any element of symmetry (such as plane of symmetry) and is optically active.

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Similar questions

Q. Assertion :Square planar complexes do not show optical isomerism. Reason: Optical isomerism is due to the absence of elements of symmetry.

Q. Which of the following square planar complex is optically active?

Q. Assertion :Trans

[C o C l_{2} (e n)_{2}]^{+}

is optically inactive. Reason: It has plane of symmetry.

Q. Assertion :cis -

[F e (e n)_{2} C l_{2}]^{+}

can form racemic mixture. Reason: cis -

[F e (e n)_{2} C l_{2}]^{+}

is optically active square planar complex.

Consider the following statements

$S_{1}$ : Generally square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess plane of symmetry

$S_{2} : Δ_{t} = \frac{4}{9} Δ_{o}$

$S_{3}$ : In octahedral complexes each electron entering the $t_{2 g}$ orbtials stabilizes the complex ion by $0.4 Δ_{o}$ and each electron entering the $e_{g}$ orbital destabilizes the complex by an amount of $0.6 Δ_{o}$

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Select the correct statement about given square planar complex :

The correct option is B It is optically active because it does not have plane of symmetryFor the given compound two geometrical isomers are possible on is cis and the other is trans.The molecule does not contain any element of symmetry (such as plane of symmetry) and is optically active.

The correct option is B It is optically active because it does not have plane of symmetry
For the given compound two geometrical isomers are possible on is cis and the other is trans.
The molecule does not contain any element of symmetry (such as plane of symmetry) and is optically active.