The correct option is C C1−N and C5−N bonds length are same but longer than C3−N bond length.
In the given compound, due to larger size of bromine atom it create a steric crowding for ortho position NO2 groups. Due to this steric hindrance the ortho positioned NO2 will get out of benzene plane. Since it is no longer in the plane it wont participitate in resonance of the molecule. But para positioned NO2 does not fell any steric effect from Br so it will involve in resonance of the molecule. Therefore C−Nin para position acquire double bond character, hence the bond length is shorter than the C−N bond length in ortho position