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B
Each boron atom lies in sp3 hyrid state
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C
Terminal H...B...H bond angle is 120∘
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D
All hydrogen in B2H6 lie in the same plane
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Solution
The correct option is C Terminal H...B...H bond angle is 120∘ Three centered two electron bond is present is diborane, B2H6.
It has two 3- centre 2 electron bond, each one consisting of the two boron atoms and a hydrogen atom sharing two electrons.
Boron is sp3 hybridised, as 4 orbitals of each boron atom will be hybridised to accomodate the electrons.
Since, each boron atom is sp3 hybridised So, terminal H−B−H bond angle is nearly 120∘
All hydrogen is B2H6 are not lie in the same. Two boron atoms and the four terminal hydrogen atoms of the molecule are in the same plane and the bridging hydrogen atoms lie above and below this plane.
Thus, this statement is incorrect.