Question

Select the displacement and double displacement reaction from the following, (a) $\mathrm{Zn}+{\mathrm{CuSO}}_4\to {\mathrm{ZnSO}}_4+\mathrm{Cu}$?

Answer 1

Displacement reaction:

A displacement reaction is a reaction in which a more reactive element displaces a less reactive element from its compound. It can be represented as:

$\mathrm{A}+\mathrm{BY}\to \mathrm{B}+\mathrm{AY}$

Double displacement reaction:

In contrast, in a double displacement reaction, two atoms are displaced from their compounds to form distinct compounds. It can be represented as:

$\mathrm{AD}+\mathrm{CB}\to \mathrm{AB}+\mathrm{CD}$

Given equation:

(a) The chemical equation is given below:

$$\begin{gathered} \mathrm{Zn}\left(\mathrm{s}\right)+{\mathrm{CuSO}}_4\left(\mathrm{aq}\right)\to {\mathrm{ZnSO}}_4\left(\mathrm{aq}\right)+\mathrm{Cu}\left(\mathrm{s}\right) \\ \mathrm{Zinc}\mathrm{Copper}\mathrm{Zinc}\mathrm{Copper} \\ \mathrm{sulphate}\mathrm{sulphate} \end{gathered}$$

Zinc (Zn) displaces copper sulphate $\left({\mathrm{CuSO}}_4\right)$ because of its high reactivity compared to copper and forms zinc sulphate. Since only one atom is displaced, it is a displacement reaction.