Select the factors of a2+7a+10.
1
a+1
2
a+2
a2+7a+10=a2+5a+2a+10=a(a+5)+2(a+5)=(a+2)(a+5) Thus, the factors of a2+7a+10 are (a+2) and (a+5).
Factorising and dividing a2+7a+10 by (a+5) gives:
Select the factors of a2+7a+10
Factors of a2−b+ab−a are