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Question

Select the general solution(s) of the trigonometric equation
secθ=1.

A
θ=(2n+1)π nZ
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B
θ=(2n+1)π2 nZ
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C
θ=2nπ nZ
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D
θ=nπ nZ
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Solution

The correct option is A θ=(2n+1)π nZ
Given that
secθ=1
1cosθ=1
cosθ=1

We know that cosθ=1θ=(2n+1)π nZ

the general solution of secθ=1 is
θ=(2n+1)π nZ

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