The correct option is
D
Products formed is a pair of enantiomer
(a) The bond strength order is:
C−H<C−D<C−T
During sulphonation electrophile react the benzene ring to form a sigma complex. To regain aromaticity, hydrogen atom is eliminated. Since
C−H bond is weaker than
C−D bond. Hence rate of sulphonation for
C6H6 is relatively faster than
C6D6.
(b) Salicylic acid gives 2,4,6-tribromophenol on treatment with
Br2/H2O.
(c) When
HCOOEt is treated with excess of
MeMgBr followed by hydrolysis, it will result in the formation of secondary alcohol.
(d)
SN2 reaction proceeds through inversion of configuration. Since only isomers is taken so it will give a single product.