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Question

Select the member of each pair that shows faster rate of SN2 reaction with KI in acetone.


(a) CH3−CH2−CH2−CH2−ClandCH3−CH∣CH3−CH2−Cl
(I)(II)
(b) CH3−CH2−CH2−ClandCH3−CH2−CH2−Br
(I)(II)
(c) CH3−CH∣CH3−CH2−CH2−ClandCH3−CH3∣C∣CH3−CH2Cl
(I)(II)
(d) CH3−CH2−CH2−Br∣CH−CH3andCH3−CH3∣CH−CH2−Br∣CH−CH3
(I)(II)

A
(a) (II) (b) (I) (C) (I) (d) (I)
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B
(a) (I) (b) (I) (C) (I) (d) (II)
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C
(a) (II) (b) (II) (C) (I) (d) (II)
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D
(a) (I) (b) (II) (C) (I) (d) (I)
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Solution

The correct option is D (a) (I) (b) (II) (C) (I) (d) (I)
The member of each pair that shows faster rate of SN2 reaction with KI in acetone is as shown.
(a) (I) (b) (II) (C) (I) (d) (I)
The rate of reaction with straight chain alkyl halides is faster than the rate of reaction with branched alkyl halides due to less steric hindrance in the case of straight-chain alkyl halides.
The rate of the reaction with alkyl bromides is higher than the rate of reaction with alkyl chlorides because Bromine is a better leaving group than Chlorine.
The rate of reaction with unhindered alkyl halides is faster than the rate of reaction with hindered alkyl halides.
Hence, the correct option is D

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