Select the most ionic and most covalent compounds respectively from the following. $C r O_{5}, M n_{2} O_{7}, P b O, S n O_{2}$

C r O_{5}, M n_{2} O_{7}

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P b O, M n_{2} O_{7}

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S n O_{2}, C r O_{5}

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All of the above.

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Solution

The correct option is B $P b O, M n_{2} O_{7}$
As anion $(O^{2 -})$ is same, the covalent character in ionic compound will depend upon the size and charge on the cation. According to Fajan's rule, $P b O$ is most ionic because $P b^{2 +}$ has less polarising power where as $M n_{2} O_{7}$ is most covalent because $M n^{7 +}$ has higher polarising power.

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C r O_{5}, M n_{2} O_{7}, P b O, S n O_{2}

C r O_{5}, M n_{2} O_{7}, P b O, P_{4} O_{10}, S n O_{2}

P b O_{2} \to P b O

Δ G_{298} < 0

S n O_{2} \to S n O

Δ G_{298} > 0

P b

S n

Consider the reactions;

P b O_{2} \to P b O, Δ G_{298} < 0;

$S n O_{2} \to S n O, Δ G_{298} < 0$

The most probable oxidation state of $P b$ and $S n$ will be :

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