Select the odd one from the given series: $3, 7, 9, 21, 27, 66, 81, 189, 243$ .

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Solution

$3, 7, 9, 21, 27, 66, 81, 189, 243 .$
There exist two alternate series.
Series I: $3, 9, 27, 81, 243$
Series II: $7, 21, 66, 189$
In series I, the numbers are the multiples of $3$ whereas in series II except $66$ , all other numbers are arrived at by multiplying the previous number by $3$ .
Hence, $63$ should replace $66$ .

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