Select the odd one out.

$(- 9) \times 5 \times 6 \times (- 3)$

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$9 \times (- 5) \times 6 \times (- 3)$

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$(- 9) \times (- 5) \times (- 6) \times 3$

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$9 \times (- 5) \times (- 6) \times 3$

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Solution

The correct option is C
$(- 9) \times (- 5) \times (- 6) \times 3$

(a) $(- 9) \times 5 \times 6 \times (- 3) = (- 45) \times (- 18) = - (- 810) = 810$ [as, -(-x) = x]
(b) $9 \times (- 5) \times 6 \times (- 3) = (- 45) \times (- 18) = 810$ [as, -(-x) = x]
(c) $(- 9) \times (- 5) \times (- 6) \times 3 = 45 \times (- 18) = - 810$
(d) $9 \times (- 5) \times 6 \times (- 3) = (- 45) \times (- 18) = 810$

So the odd one out is option (c).

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Similar questions

Question 28

Encircle the odd one of the following:

(a) $(- 9) \times 5 \times 6 \times (- 3)$
(b) $9 \times (- 5) \times 6 \times (- 3)$
(c) $(- 9) \times (- 5) \times (- 6) \times 3$
(d) $9 \times (- 5) \times (- 6) \times 3$

Q. If A = (4x + y - 12xy + 9z),
B = (3y + 9x + 6xy - 7z),
C = (6x + 6y + 9xy)
Find 2A - 3B + 4C.

1-[7-{5-3(9-(3-6))}]

{(81)}^{- 1} \times 3^{- 5} \times 3^{9} \times (64)^{\frac{5}{6}} \times {(\sqrt[3]{3})}^{6}

Q. If A =

4 x^{2} + y^{2} - 12 x y + 9 x

,
B =

3 y^{2} + 9 x^{2} + 6 x y - 7 x

,
C =

6 x^{2} + 6 y^{2} + 9 x y

Find 2A-3B+4C.

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