CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Select the option that contains the factor of 4x3+4x2x1


A

(x+12)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(x3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

(2x1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

(2x2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

(2x1)


Let P(x) = 4x3+4x2x1

Factorise the polynomial to find the factors.

4x3+4x2x1

=4x2(x+1)1(x+1)

[Taking 4x2 as common in the first two terms and -1 as common in the last two terms]

=(x+1)(4x21)

=(x+1)(2x+1)(2x1)

(x+1)(2x+1)(2x1) are factors.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorization of Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon