wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Select the options in which the elements given in the square bracket have the same oxidation number.


A

K[Mn]O4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

[Mn]O2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

[Mn]2O3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

[Mn]2O7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A

K[Mn]O4


D

[Mn]2O7


Since the options given to us are all electrically neutral compounds the sum of oxidation number for all the elements should be equal to zero. Let's solve all the options to see which options have the same oxidation number. You need to know that the oxidation number for K and O is +1 and -2 respectively.

(1) K[Mn]O4, let the oxidation number of Mn be x.

+1+x+4×(2)=0

x=+7

(2) [Mn]O2, let the oxidation number of Mn be x.

x+2×(2)=0

x=+4

(3) [Mn]2O3, let the oxidation number of Mn be x.

2×x+3×(2)=0

x=+3

(4) [Mn]2O7, let the oxidation number of Mn be x.

2×x+7×(2)=0

x=+7

So from the given options the oxidation number of Mn in K[Mn]O4 and [Mn]2O7 is same and is equal to +7.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calculating Oxidation Number
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon