Question

Select whether the following combinations of reactants will react by substitution $(S_{N^1}or{S}_{N^2}$ mechanism), elimination ($E_{1}or{E}_2$ mechanism).
$(C{H}_3{)}_{2}CHC{H}_{2}C{H}_2-OH\underset{{50}^{0}C}{\overset{HBr48\%in{H}_{2}O}{\to }}$

• A. $S_{N^1}$
• B. $S_{N^2}$
• C. $E_1$
• D. $E_2$

Answer 1

The correct option is A $S_{N^1}$

$S{N}^1$ mechanism is followed in the reaction rearrangement of $1^o$ carbocation to $2^o$ carbocation takes place to give the product.