The correct option is C {x:x is a positive multiple of 7} and {7,14,21,28,...}
We know two sets are equal if they have same elements.
While two sets are equivalent if they have same cardianality.
Let's take the pairs one by one.
A.{2,10,15,20} & {10,20,15,2}
Here, if we re-arrange the second set, we get them as:
{2,10,15,20} which is identical to the first set.
This means that the two sets are equal and hence equivalent as well.
B.{a,b,c,d,e} & {a,c,d,e,a}
Here, removing the duplicates from the second set we have the two sets as:
{a,b,c,d,e} & {a,c,d,e}
Here, the first set has 5 elements while the second set has 4 elements.
Hence the two sets are neither equal nor equivalent.
C.{x:x is a positive multiple of 7} and {7,14,21,28,...}
Writing the first set in roster form, we can write it as:
{7,14,21,28,...} & {7,14,21,28,...}
Hence, the two sets are identical and hence equal which means they are equivalent as well.