Question

Select wrong statement.

• A. Oxidation number of $C$ in sucrose $\left(C_{12}{H}_{22}{O}_{11}\right)$ is zero
• B. Oxidation number of carbon in carbon suboxide $\left(C_3{O}_2\right)$ is $4/3$
• C. Oxidation no. of $N\&Cl$ in $NOCl{O}_4$ respectively are $+2\&+7$
• D. None of these

Answer 1

Answer: (B), (C)

The correct options are
B Oxidation number of carbon in carbon suboxide $\left(C_3{O}_2\right)$ is $4/3$
C Oxidation no. of $N\&Cl$ in $NOCl{O}_4$ respectively are $+2\&+7$

Answer is $B$ & $C$
Oxidation number of carbon in carbon suboxide is, $O=C=C=C=O-2+20+2-2$

Average oxidation state at $C=\frac{+2+2+0}{3}=+1.3$

Oxidation number of $N$ and $Cl$ in $NOCl{O}_4$

$NOCl{O}_4$ made up of $N{O}^{+}$ and $Cl{O}^{-}$

$\therefore$ In $N{O}^{+},$ oxidation number of nitrogen is, $x+1(-2)=+1x=1+3=+4$

In $Cl{O}^{-}$, oxidation number of chlorine is $x+4(-2)=-1x=-1+8=+7$

Oxidation number of $C$ in sucrose is $12x+22+11(-2)=0x=0$