Semi-circular lawns are attached to the edges of a rectangular field measuring $42 m \times 35 m$ . The area of the total field is

3818.5 m^{2}

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8318 m^{2}

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5813 m^{2}

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1358 m^{2}

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Solution

The correct option is A $3818.5 m^{2}$

Total area of field = Area of rectangular part + Area of small circle + Area of large circle
= $35 \times 42 + π \times {(17.5)}^{2} + π \times {(21)}^{2}$
$= 1470 + 962.5 + 1386$
$= 3818.5 m^{2}$

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Semi-circular lawns are attached to the edges of a rectangular field measuring 42m×35m. The area of the total field is

The correct option is A 3818.5 m2Total area of field = Area of rectangular part + Area of small circle + Area of large circle= 35×42+π×(17.5)2+π×(21)2=1470+962.5+1386=3818.5m2

Semi-circular lawns are attached to the edges of a rectangular field measuring $42 m \times 35 m$ . The area of the total field is

The correct option is A $3818.5 m^{2}$

Total area of field = Area of rectangular part + Area of small circle + Area of large circle
= $35 \times 42 + π \times {(17.5)}^{2} + π \times {(21)}^{2}$
$= 1470 + 962.5 + 1386$
$= 3818.5 m^{2}$