Question

Semicircular ring of radius $0.5m$ is uniformly charged with a charge of $1.4\times {10}^{-9}C$. The electric field intensity at centre of this ring is:

• A. $zero$
• B. $320V/M$
• C. $64V/M$
• D. $32V/M$

Answer 1

The correct option is

D

$32V/M$

Semi circular ring radius $=0.5m,$

As we know,

Q=1.4×10−9CQ=1.4\times { 10 }^{

$E=$ electric field intensity due to arc of a ring

=$\frac{\left(2KQsin\frac{\theta }{2}\right)}{\theta R^2}$

=$\frac{(2(9\times {10}^9)\times 1.4\times {10}^{-9})}{\left(3.14\right){\left(0.5\right)}^2}$ =32 v/m