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Question

Separate 178 into two parts so that the first part is 8 less than twice the second part.

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Solution

Let the second part be 'x'

First part is 8 less than twice the second part

Then the first part will be 2x-8

By the problem we have sum of first part and second part is 178

x+2x-8=178

3x-8=178

3x=178+8=186

x=186/3 = 62

So the first part is 2x-8 = 2(62)-8 = 124-8=116

Second part is x = 62

Answer : 116,62

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