Question

Sequence in Krebs cycle is

• A. $\alpha$ -Ketoglutaric acid -->Isocitric acid -->Oxalosuccinic acid
• B. Isocitric acid --> Oxalosuccinic acid -->$\alpha$ -Ketoglutaric acid
• C. Isocitric acid --> $\alpha$-Ketoglutaric acid --> Oxalosuccinic acid
• D. Oxalosuccinic acid --> Isocitric acid --> $\alpha$-Ketoglutaric acid.

Answer 1

The correct option is B Isocitric acid --> Oxalosuccinic acid -->$\alpha$ -Ketoglutaric acid

During the Krab cycle, the isocitric acid is converted to oxalosuccinic acid where a molecule of energy is converted to NADH and the enzyme used here is isocitrate dehydrogenase.

This oxalosuccinic acid is converted into Alpha-ketoglutaric acid by the enzyme isocitrate dehydrogenase and during this process, a carbon dioxide molecule is released.

So, the correct option is 'Isocitric acid --> Oxalosuccinic acid -->α -Ketoglutaric acid'