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B
I−C;II−D;III−B;IV−A
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C
I−D;II−C;III−B;IV−A
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D
I−A;II−B;III−C;IV−D
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Solution
The correct option is CI−C;II−D;III−B;IV−A A) NaOH→ strong base pH=14 B) Na2CO3→ Anionic hydrolysis CO2−3+H2O→H2CO3+OH− ∴pH>7 C) CH3COONH4 Salt of Weak Acid and Weak base with ka=kb ∴ Neutral, i.e., →pH=7 D) None have pH<7.