Question

Set -1 (solution) Set-2 (Hydrolysis type)
I) Aqueous solution of $AlC{l}_3$ A)only anionic
II) Aqueous solution of $(N{H}_4{)}_{2}C{O}_3$ B) only cationic
III) Aqueous solution of NaCl C) Neither cationic nor anionic hydrolysis.
IV) Aqueous solution of $C{H}_{3}COONa$ D) Both cationic and anionic hydrolysis.
The correct match is :

• A. I-D; II-C ; III-B ; IV-A
• B. I-B ; II-D; III-C; IV-A.
• C. I-A; II-B; III-C; IV-D.
• D. I-C; II-A; III-B; IV-C.

Answer 1

The correct option is B I-B ; II-D; III-C; IV-A.

1] $AlC{l}_3\to HCl$ strong acid
$Al(OH{)}_3\to$ weak base
$\therefore$ Cationic hydrolysis
2] $\left(N{H}_4\right)C{O}_3\to N{H}_{4}OH$ weak base
$H_{2}C{O}_3$ weak acid
$\therefore$ Both type of hydrolysis
3) $NaCl\to NaOH\to$ strong base
$HCl\to$ strong acid
$\therefore$ No hydrolysis
4) $C{H}_{3}COONa\to C{H}_{3}COOH\to$ weak acid
$NaOH\to$ strong base
$\therefore$ Anionic hydrolysis.

Option B is correct.