Set A has m elements and set B has n elements.If the total number of subsets of A is 112 more than the total number of subsets of B, then the value of m×n is
A
28.0
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B
28
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C
28.00
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Solution
A and B are two sets having m,n elements respectively.
No.of subsets of A=2m
No.of subsets of B=2n 2m=2n+112 2m−2n=112 2n(2m−n−1)=112 2n(2m−n−1)=24(23−1) n=4 m−4=3⇒m=7 ⇒m×n=28