Question

set of irrational numbers is $\{\sqrt{8},\pi \}$

• A. True
• B. False

Answer 1

The correct option is A True

Rational numbers are those numbers which can be expressed in the form $\frac{p}{q}$, where p and q are integers and $q\ne 0$

Numbers which are not rational numbers are called irrational numbers.
From the given set of numbers, $-6,-5\frac{3}{4},-\frac{3}{5},-\frac{3}{8},0,\frac{4}{5},1,1,\frac{2}{3},3.01,8.47$ are clearly rational numbers are they can be written in $\frac{p}{q}$ form.
Now, $-\sqrt{4}=-2$ which is also a rational number.
And, $\sqrt{8}=2\sqrt{2}$ is not a rational number.
Also, $\pi$ is not a rational number.
Hence, the irrational numbers in the given set are {$\sqrt{8},\pi$}