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Byju's Answer
Standard XII
Mathematics
Definition of Functions
Set of values...
Question
Set of values of
x
for which the function
f
(
x
)
=
1
x
+
2
sin
−
1
x
+
1
√
x
−
2
exists is
A
R
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B
R
−
{
0
}
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C
ϕ
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D
R
−
{
1
}
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Solution
The correct option is
D
ϕ
f
(
x
)
=
2
sin
−
1
x
+
1
√
x
−
2
+
1
x
x
≠
0
for
1
x
−
1
⩽
x
⩽
1
for
sin
−
1
x
√
x
−
2
≠
0
and
x
−
2
>
0
for
1
√
x
−
2
x
>
2
n combining, we get domain of
f
(
x
)
is
ϕ
.
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0
Similar questions
Q.
A function
f
:
R
→
R
+
satisfying
f
(
x
+
y
)
=
f
(
x
)
f
(
y
)
∀
x
,
y
∈
R
,
f
(
0
)
=
1
,
f
′
(
0
)
=
2
, then
Q.
The range of the function f(x) given by
f
(
x
)
=
1
√
x
−
[
x
]
i
s