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Question

Set of values of x for which the function f(x)=1x+2sin1x+1x2 exists is

A
R
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B
R{0}
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C
ϕ
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D
R{1}
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Solution

The correct option is D ϕ
f(x)=2sin1x+1x2+1x
x0 for 1x
1x1 for sin1x
x20 and x2>0 for 1x2
x>2
n combining, we get domain of f(x) is ϕ.

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