Set the following in increasing order of their pKa values x CH3O-O-SOH y CH3O-COH z CH3OH -

The correct option is B x Higher the value of pK_a , lower is the acidity. #160;In the given compounds CH_3OH is least acidic due to less stabilit ...

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Standard XII

Chemistry

Nucleophilic Substitution in Alkyl Halides

Set the follo...

Question

Set the following in increasing order of their $p^{K_{a}}$ values
$(x) C H_{3} O | | S | | O O H (y) C H_{3} O | | C O H (z) C H_{3} O H$ :

y > x > z

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x < y < z

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y > z > x

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x < z < y

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Solution

The correct option is B x < y < z
Higher the value of $p K_{a}$ , lower is the acidity.

In the given compounds $C H_{3} O H$ is least acidic due to less stability of $C H_{3} O^{-}$ ion (+I effect of $C H_{3}$ ) therefore has highest $p K_{a}$ .

In $C H_{3} C O O^{-}$ and $C H_{3} S O_{3}^{-}$ the negative charge is in conjugation with $π$ bond making them strong acids.

$C H_{3} S O_{3} H$ is strongest acid as the highly electron negative group $S O_{3}$ makes the hydrogen highly acidic.

Therefore it has least value of $p K_{a}$ and the order of $p K_{a}$ values is $x < y < z$ .

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Similar questions

(x)

C H_{3} - O | | S | | - O O - H

(y)

C H_{3} - O | | C - O - H

(z)

C H_{3} - O H

Set the following in increasing order of their

p K_{a}

values.

Q. Prove that

\begin{matrix} (x + y)^{2} & z x & z y z x & (z + y)^{2} & x y z y & x y & (z + x)^{2} \end{matrix}

2 x y z (x + y + z)^{3}

Q. Using properties of determinants, prove that

∣ ∣ ∣ ∣ ∣ \begin{matrix} (x + y)^{2} & z x & z y z x & (z + y)^{2} & x y z y & x y & (z + x)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = 2 x y z (x + y + z)^{3}

Q. Arrange the following in increasing order of their

p K_{a}

values.
(x)

(y)

(z)

C H_{3} - O H

Q. Solve the following equations :

x (x + y + z) = a^{2}, y (x + y + z) = b^{2}, z (x + y + z) = c^{2} .

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Set the following in increasing order of their pKa values(x)CH3O||S||OOH(y)CH3O||COH(z)CH3OH :

Set the following in increasing order of their $p^{K_{a}}$ values
$(x) C H_{3} O | | S | | O O H (y) C H_{3} O | | C O H (z) C H_{3} O H$ :